(8/x^2)+(7/x)=0

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Solution for (8/x^2)+(7/x)=0 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+8/(x^2) = 0

7*x^-1+8*x^-2 = 0

t_1 = x^-1

8*t_1^2+7*t_1^1 = 0

8*t_1^2+7*t_1 = 0

DELTA = 7^2-(0*4*8)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-7)/(2*8) or t_1 = (-49^(1/2)-7)/(2*8)

t_1 = 0 or t_1 = -7/8

t_1 = -7/8

x^-1+7/8 = 0

1*x^-1 = -7/8 // : 1

x^-1 = -7/8

-1 < 0

1/(x^1) = -7/8 // * x^1

1 = -7/8*x^1 // : -7/8

-8/7 = x^1

x = -8/7

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -8/7

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